Question 1075548
Remember the log rule
{{{logx(3)+logx(4)=log(3*4)}}}

Thus
{{{log5(2x+1)+log5(x+2)=1}}}
{{{log5(2x^2+4x+x+2)=1}}}
{{{5^1=2x^2+5x+2}}}
Now just factor and solve from x there. Hope this helped.