Question 1075464
.
If the zeroes of the quadratic {{{highlight(cross(polynomials))}}} polynomial x^2+(a+1)x+b are 2 and -3,then find the values of a and b
~~~~~~~~~~~~~~~~~~~~~~~~~~~



Use the Vieta's theorem"


<pre>
    The sum of roots of a quadratic polynomial is equal to the coefficient at x with the opposite sign;
    The product of the roots is equal to the constant term.
</pre>


In your case it gives  b = 2*(-3) = -6.


a+1 = -(2 + (-3)) = -(-1) = 1; hence, a = 0.


<U>Answer</U>. a = 0; b = -6.