<PRE><B>Question 1075453</B>
let l be the length of the old tile and w be the width of the old tile, then
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The area of the new tile minus the area of the old tile equals 39
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(l+3)(w+3) -lw = 39
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lw +3l +3w +9 -lw = 39
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3l +3w = 30
:
l +w = 10
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We know that the area of the old tile is maximized when l = 5 and w = 5
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A) 5 inches by 5 inches
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B) The area of a new tile is (5+3)(5+3) = 64 square inches
Note that 25 + 39 = 64
5120 / 64 = 80 new tiles
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