Question 1075330
y''=6
y'=6x + C
y=3x^2+some value of x
y=3x^2-4x has a first derivative of 6x-4 which is 8 when evaluated at x=2
but the function equals 16 when x=2, so the constant term is 12
y=3x^2-4x+12
{{{graph(300,300,-10,10,-10,30,3x^2-4x+12,8x)}}}