Question 1859
1. 49logx

2. log{{{(3x)^(1/3)}}} + log{{{x^(1/4)}}}. These can then be combined into 1 log as follows:


   log{{{(3x)^(1/3)x^(1/4)}}}

Not exactly neat, but it answers the question.

3. -log18 (since log1 is zero)
this is fine, although you can remove the -ve sign by writing this as log(1/18)

cheers
Jon.