Question 1075280
I would substitute the numbers or graph for the real numbers
for -2: -8-8-8-8 does not equal 0, so not a root
2i: 8i^3-8i^2+8i-8=-8i+8+8i-8 does work.
+2 is a root, so (x-2) is a factor
the other factor is (x^2+4)
The roots are 2, 2i, and -2i
For the purposes of this question, B.
{{{graph(300,300,-10,10,-10,10,x^3-2x^2+4x-8)}}}