Question 1075218
Divide by the magnitude of {{{v}}}.
{{{abs(v)=sqrt(5^2+7^2)=sqrt(25+49)=sqrt(74)}}}
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{{{v[u]}}}=<{{{5/sqrt(74)}}},{{{7/sqrt(74)}}}>
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{{{v[u]}}}=<{{{(5/74)sqrt(74)}}},{{{(7/74)sqrt(74)}}}>