Question 1075180
Find the equation of a circle whose radius is 5 and the center lies on the positive side of x-axis at a distance 5 from the origin
<pre>With a radius of 5 units from the center, and the center being in the 1st quadrant, a point on the circle will be (0, 0).
The radius in the 1st quadrant will be the hypotenuse of a 3-4-5 right triangle, with the longer side being 4 units and on the x-axis. Thus the center is: (4, 3)
Therefore, the equation of the circle: {{{(x - h)^2 + (y - k)^2 = r^2}}} becomes: {{{highlight_green((x - 4)^2 + (y - 3)^2 = 25)}}}