Question 1075139
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{{{highlight(cross(Right))}}} Write the equation of the circle with a diameter having 2 end points (18,-3) , (4,3)
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The center is  {{{(x[1]+x[2])/2}}} = {{{(18+4)/2}}} = {{{22/2}}} = 11,

               {{{(y[1]+y[2])/2}}} = {{{((-3) + 3)/2}}} = {{{0/2}}} = 0.


The center is (x,y) = (11,0).


The radius is {{{sqrt((18-11)^2 + (3-0)^2)}}} = {{{sqrt(7^2 + 3^2)}}} = {{{sqrt(49+9)}}} = {{{sqrt(58)}}}.


The equation of the circle is 

{{{(x-11)^2 + y^2)}}} = 58.
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