Question 1075126
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Since there are 28 students and 13 of them are female, the probability that a female will be selected is *[tex \Large \frac{13}{28}].  Then there is a *[tex \Large \frac{7}{28}\ =\ \frac{1}{4}] probability that the student will be a male, and a *[tex \Large \frac{8}{28}\ =\ \frac{2}{7}] probability that the student selected will be in some stage of the transgender process such that, at the time of the selection, the student was neither male nor female.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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