<PRE><B>Question 94584</B>
A passenger train can travel 325 mi in the same time a freight train takes to travel 200 mi. If the speed of the passenger train is 25 mi faster than the speed of the freight train, find the speed of each. 
:
Let s = speed of the freight
Then
(s+25) = speed of the pass train
:
They are giving the time as the same for both trains, make a time equation from this fact: 
Time = Dist/speed
:
{{{325/((s+25))}}} = {{{200/s}}}
:
Cross multiply and you have:
:
325s = 200(s+25)
:
325s = 200s + 5000
:
325s - 200s = 5000
:
125s = 5000
:
s = 5000/125
:
s = 40 mph, speed of the freight
and
(s+25) = 65 mph, speed of the pass train
:
:
Check solutions, is the time the same?
200/40 = 325/65
5 = 5
</PRE>