Question 1075151
3(^2x+2)-28*3^x=-3
3^(2x+2)-28*3^x=-3
{{{3^(2x+2)-28*3^x = -3}}}
{{{9*3^(2x)-28*3^x + 3 = 0}}}
Sub u for 3^x
{{{9u^2 - 28u + 3 = 0}}}
(9u - 1)*(u - 3) = 0
u = 3
3^x = 3
x = 1
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u = 1/9
3^x = 1/9
x = -2