Question 1075127
The coin toss has two equally likely outcomes, so P{head} = 1/2

The die has 6 equally likely outcomes, so P{6 tossed} = 1/6

Together, the probability of getting a head on the coin toss and a 6 on the die toss is the product of these two:   P{6 tossed and head tossed } =  (1/6)(1/2) = {{{ highlight(1/12) }}}
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This makes sense since there are 2*6 = 12 equally likely outcomes, and the problem simply asks for the probability of getting one specific outcome out of the 12.