Question 1074994
You solve logarithms with exponentials, here is the relationship, assuming you mean the natural logarith of 5. 
:
The base of a natural logarithm is e (the number e, 2.718...)
therefore:
log_b(x) = y
b^ŷ = x
log_e 5 = y
e^ŷ = 5
or if you want to use the numerical equivalent of e to three decimals:
2.718^ŷ = 5