Question 94675
log9(1/3)=y
log9(3^-1)=y
-log9(3)=y
3=9^-y
-log10(3)/log10(9)=y
-log10(3)/log10(3^2)=y
-log10(3)/[2*log10(3)]=y
-1/2=y
{{{graph(300,300,-4,4,-1,1,log(9,1/3),2^(x-6) - 1/2)}}}
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e^x * 4e^(2x + 1)
4(e^x)e^(2x + 1)
4e^(x + 2x + 1)
4e^(3x + 1)
{{{graph(300,300,-6,6,-1,6,2.718^x * 4*2.718^(2x + 1),4*2.718^(3x + 1))}}}