Question 94596
Assume you mean:
{{{((2x-10))/((3x^2-x-14))}}} +  {{{7/((3x-7))}}} = {{{8/((x+2))}}}
:
factor the quadratic and you have:
{{{((2x-10))/((3x-7)(x+2))}}} +  {{{7/((3x-7))}}} = {{{8/((x+2))}}}
:
Multiply the equation by (3x-7)(x+2) to get rid of the denominators, you have:
:
(2x-10) + 7(x+2) = 8(3x-7)
:
2x - 10 + 7x + 14 = 24x - 56; multiplied what's inside the brackets
:
9x + 4 = 24x - 56
:
9x - 24x = -56 - 4
:
-15x = -60
:
x = -60/-15
:
x = + 4