Question 1074846
4(3-x)^(4/3)-5 = 59



{{{4(3-x)^(4/3)-5 = 59}}}


{{{4(3-x)^(4/3)=64}}}


{{{(3-x)^(4/3)=16}}}


{{{3-x=(16)^(3/4)}}}


{{{3-x=(16^(1/4))^3}}}


{{{3-x=(0+- 2)^3}}}


{{{-x=-3+- 2^3}}}


{{{x=3+- 2^3}}}


{{{x=3+- 8}}}


<s>Either</s>   {{{-5}}} <s>or</s> {{{cross(11)}}}




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x=11 will not work in the original equation.  It would means trying to take quarter root of a negative number.