Question 1074759
If {{{z[1]=a+bi}}} and {{{z[2]=c+di}}} and
{{{abs(z[1])=abs(z[2])}}}
Then,
{{{sqrt(a^2+b^2)=sqrt(c^2+d^2)}}}
{{{a^2+b^2=c^2+d^2}}}
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1. {{{a=b}}} and {{{c=d}}}, not necessarily
2. {{{a=b}}}, not necessarily
3. {{{c=d}}}, not necessarily