Question 1074730
Tan_1(1/√3)
<pre>I retract. 
{{{sin (30^o)/cos (30^o) = (1/2)/(sqrt(3)/2) = (1/2) * (2/sqrt(3)) = 1/sqrt(3)}}}. 
Therefore, if it's {{{tan^(- 1)(1/sqrt(3))}}}, then angle = {{{highlight_green(matrix(1,3, 30^o, or, pi/6))}}}