Question 1074728
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<pre>
Rectangular equation is 

{{{x^2/5^2 + y^2/3^2}}} = 1.
</pre>

Ellipse with the center at the origin, (x,y) = (0,0).


{{{graph( 330, 330, -8.5, 8.5, -8.5, 8.5,
          3*sqrt(1-(x/5)^2), -3*sqrt(1-(x/5)^2)
)}}}


Ellipse {{{x^2/5^2 + y^2/3^2}}} = 1.


y = + {{{3*sqrt(1-(x/5)^2)}}} and y = - {{{3*sqrt(1-(x/5)^2)}}}.