Question 1073996
Use Cramer's rule,
{{{A=(matrix(3,3,
2,-3,7,
3,0,1,
1,2,-2))}}}
{{{abs(A)=17}}}
.
.
.
{{{A[x]=(matrix(3,3,
-1,-3,7,
6,0,1,
-1,2,-2))}}}
{{{abs(A[x])=53}}}
.
.
.
{{{A[y]=(matrix(3,3,
2,-1,7,
3,6,1,
1,-1,-2))}}}
{{{abs(A[y])=-92}}}
.
.
.
{{{A[z]=(matrix(3,3,
2,-3,-1,
3,0,6,
1,2,-1))}}}
{{{abs(A[z])=-57}}}
.
.
.So,
{{{x=abs(A[x])/abs(A)=53/17}}}
.
.
{{{y=abs(A[y])/abs(A)=-92/17}}}
.
.
{{{z=abs(A[z])/abs(A)=-57/17}}}
.
.