Question 1074634
Use Cramer's rule,
{{{A=(matrix(3,3,
3,2,4,
2,-2,1,
-1,3,-1))}}}
{{{abs(A)=15}}}
.
.
.
{{{A[x]=(matrix(3,3,
9,2,4,
1,-2,1,
1,3,-1))}}}
{{{abs(A[x])=15}}}
.
.
.
{{{A[y]=(matrix(3,3,
3,9,4,
2,1,1,
-1,1,-1))}}}
{{{abs(A[y])=15}}}
.
.
.
{{{A[z]=(matrix(3,3,
3,2,9,
2,-2,1,
-1,3,1))}}}
{{{abs(A[z])=15}}}
.
.
.
So,
{{{x=abs(A[x])/abs(A)=15/15=1}}}
.
.
{{{y=abs(A[y])/abs(A)=15/15=1}}}
.
.
{{{z=abs(A[z])/abs(A)=15/15=1}}}
.
.