Question 94579
{{{5/(x+6)}}} + {{{2/(x^2+7x+6)}}} = {{{3/(x+1)}}}
:
Factor the quadratic;
{{{5/(x+6)}}} + {{{2/(x+6)(x+1)}}} = {{{3/(x+1)}}}
:
Multiply thru by (x+6)(x+1)
(x+6)(x+1)*{{{5/(x+6)}}} + (x+6)(x+1)*{{{2/(x+6)(x+1)}}} = (x+6)(x+1)*{{{3/(x+1)}}}
:
Cancel out the denominators and you have:
5(x+1) + 2 = 3(x+6)
:
5x + 5 + 2 = 3x + 18
:
5x + 7 = 3x + 18
:
5x - 3x = 18 - 7
:
2x = 11
:
x = 11/2