Question 1074571
{{{y=a(x-2)^2-1}}}


{{{y+1=a(x-2)^2}}}
{{{(y+1)/(x-2)^2=a}}}
{{{a=(1+1)/(3-2)^2}}}
{{{a=2}}}


f(x)=2(x-2)^2-1
{{{2(x^2-4x+4)-1}}}
{{{2x^2-8x+8-1}}}
{{{highlight(f(x)=2x^2-8x+7)}}}


{{{graph(300,300,-6,6,-6,6,2x^2-8x+7)}}}