Question 94618
 I am struggling with this problem I need to solve 
it using quadratic formula. Any help would be 
appreciated. 

xē – 10x – 1 = -10 

<pre><font size = 4><B>

         xē - 10x - 1 = -10

Get 0 on the right by adding 10 to both sides


           xē - 10x + 9 = 0

That COULD be done by factoring, but since you
specified "the quadratic formula":

The quadratic formula is:
                  ______ 
            -b ą <font face = "symbol">Ö</font>bē-4ac
        x = —————————————
                2a 

where a = 1; b = -10; c = 9

                       ______________
             -(-10) ą <font face = "symbol">Ö</font>(-10)ē-4(1)(9)
        x = ——————————————————————————
                      2(1) 
                   ______ 
             10 ą <font face = "symbol">Ö</font>100-36
        x = ——————————————
                   2

                   __ 
             10 ą <font face = "symbol">Ö</font>64
        x = ———————————
                 2 

                   
             10 ą 8
        x = ————————
               2 


                        
Using the +, x = {{{(10+8)/2}}} = {{{18/2}}} = 9
                       
Using the -, x = {{{(10-8)/2}}} = {{{2/2}}} = 1

Those are the two solutions.

Edwin</PRE>