Question 1074561
{{{(x+3)^2+(y+2)^2=25}}}


x=1;
{{{(1+3)^2+(y+2)^2=25}}}

{{{(y+2)^2=25-16}}}

{{{y+2=0+- 3}}}

{{{y=-2-3}}} or {{{y=-2+3}}}


{{{y=-5}}}, or {{{y=1}}}








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