Question 1074483
Rational coefficients means complex roots come in complex conjugate pairs.
{{{f(x)=a(x-6)(x+i)(x-i)}}}
{{{f(x)=a(x-6)(x^2+1)}}}
So then find a using the point,
{{{-10=a(2-6)(2^2+1)}}}
{{{-10=a(-4)(5)}}}
{{{a=1/2}}}
..
.
{{{f(x)=((x-6)(x^2+1))/2}}}

{{{f(x)=x^3/2-3x^2+x/2-3}}}