Question 1074451
Starts at {{{-8}}} and increments by {{{-3}}}
So,
{{{a[1]=-8}}}
{{{d=-3}}}
{{{a[n]=a[1]+(n-1)d}}}
{{{a[n]=-8+(n-1)(-3)}}}
{{{a[n]=-8-3n+3}}}
{{{a[n]=-5-3n}}}
{{{a[n]=-(3n+5)}}}