Question 94564
Let x=Julia's age now
x-5=Julia's age five years ago
x+5=Julia's age five years from now

And let y=Karla's age now
y-5=Karla's age five years ago
y+5=Karla's five years from now

Now we are told the following:

x-5=2(y-5)---------------------------eq1
y+5=(3/4)(x+5)----------------------------eq2

simplify eq1:

x-5=2y-10  add 5 to both sides
x=2y-5----------------------eq1

simplify eq2:
4y+20=3x+15  subtract 20 from both sides
4y=3x-5------------------------eq2

substitute x=2y-5 into eq2

4y=3(2y-5)-5  get rid of parens

4y=6y-15-5  subtract 6y from both sides
-2y=-20  divide both sides by -2

y=10----------------------Karla's age now

x=2y-5
x=2*10-5
x=15--------------------------Julia's age now

CK

Five years ago:

Karla was 5 and Julia was 10
Julia was twice as old as Karla

Five years from now:

Karla will be 15 and Julia will be 20

15 is 3/4 of 20

Hope this helps----ptaylor