Question 1074241
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June is 15 years older than Chuck is now. 5 years from now June will be twice as old as Chuck. Find their ages now.  
I used a number line to get the answer.  25 June.  10 Chuck.  I can't figure out the equation. 
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<pre>
Now:               J = C + 15.     (1)   ("June is 15 years older than Chuck is now. ")

5 years from now:  J+5 = 2*(C+5)   (2)   ("5 years from now June will be twice as old as Chuck.")


Substitute (1) into (2). You will get

(C+15) + 5 = 2(C+5),

C + 20 = 2C + 10,

20 - 10 = 2C - C  --->  C = 10.

<U>Answer</U>. Chuck is 10 years old now. June is 10+15 = 25 years now.
</pre>


There is a bunch of lessons on age word problems 

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Age-problems-and-their-solutions.lesson>Age problems and their solutions</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Fresh-formulation-of-a-traditional-age-problem.lesson>A fresh formulation of a traditional age problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Really-intricate-age-word-problem.lesson>Really intricate age word problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/age/Selected-age-word-problems-from-the-archive.lesson>Selected age word problems from the archive</A>

in this site.


Read them and become an expert in solving age problems.


Also, you have this free of charge online textbook in ALGEBRA-I in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-I - YOUR ONLINE TEXTBOOK</A>.


The referred lessons are the part of this online textbook under the topic "<U>Age word problems</U>".