<PRE><B>Question 94535</B>
multiply

2x^2 - x - 3/3x^2 + 7x + 4  .  3x^2 - 11x - 20/4x^2 - 9


Factorize :

2x^2 - x - 3

2x^2 +2x -3x - 3 

2x(x + 1) -3(x + 1)

( 2x - 3) ( x+ 1) are the factors 
________________

3x^2 + 7x + 4

3x^2 + 3x +4x + 4

3x(x+1) +4(x+1)

(3x+4)(x+1) are the factors
__________

3x^2 - 11x - 20

3x^2 -15x + 4x -20

3x( x - 5) + 4 (x- 5)

( 3x +4) ( x-5) are the factors
______________

4x^2 -9 

(2x)^2-(3)^2

(2x+3)(2x-3) are the factors
___________

now  we have,

(2x-3) (x + 1)/(3x+4)(x+1) *(3x+4)(x-5)/(2x-3)(2x+3)


(2x-3) gets cancelled

(3x+4) gets cancelled

(x+1) gets cancelled

now we have,

(x-5)/(2x + 3)

Hence the solution is (x-5)/(2x + 3)







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