Question 1074191
In quadrant 1, with {{{x>=0}}} and {{{y>=0}}} ,
{{{abs(x)+abs(y)=5}}} simplifies to {{{x+y=5}}} ,
which is the equation of the straight luine connecting (0,5) to (5,0) .
It is obvious that the graph of {{{abs(x)+abs(y)=5}}}
is symmetrical about the x-axis
(because replacing {{{-y}}} for {{{y}}} gives the same equation) .
It is similarly symmetrical about the y-axis for the similar reason taht
replacing {{{-x}}} for {{{x}}} yields the same eqiuation.
With all of the above, the conclusion is that
the graph is a square with corners pointing up, down, left and right.
{{{drawing(300,300,-6,6,-6,6,
grid(1),blue(line(0,5,5,0)),
blue(line(0,5,-5,0)),blue(line(0,-5,5,0)),
blue(line(0,-5,-5,0))
)}}}