Question 94538
6p - 18/9p (divided by) 3p - 9/p^2 + 2p


6(p-3)/9p (divided by ) 3(p -3) /p(p+2)


2(p-3)/ 3p (multiplied by ) p(p+2)/3(p-3) take inverse of 3(p-3) /p(p+2)


(p-3) gets cancelled

p gets cancelled

 now we have 2(p+2)/9

(2p+4)/9 is the solution.