Question 1074013
First, we find the diagonal of the "floor" of the box, which is:
2²+4²=4+16=20
&#8730;20 is the lenght of the floor. Now, we can raise it 3 cm, which gives us a diagonal of:
(&#8730;20)²+3²=20+9=29
This gives us:
&#8730;29, or 5.38516 cms. as the length of the longest needle that can fit into the box. &#9786;&#9786;&#9786;&#9786;