Question 1074080
 the length of a rectangle is 7cm more than twice the width.
L = 2w+7
 the perimeter is 86cm. find the dimensions of the rectangle
2L + 2W = 86
simplify, divide by 2
L + w = 43
replace L with (2w+7)
(2w+7) + w = 43
3w = 43 -  7
3w = 36
w = 36/3
w = 12 cm is the width
then
L = 2(12) + 7
L = 31 cm is the length
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Check the solution with these dimensions
2(31) + 2(12) = 
62 + 24 = 86