Question 1074036
Point (-9,-2) is at {{{1}}} unit distance from line {{{x=-1}}} ,
so the circle will be a circle of radius {{{R=1}}}
centered at point {{{C(-9,-2)}}} , which has {{{system(x[C]=-9,y[C]=-2)}}} .
{{{drawing(600,300,-14,6,-7,3,grid(1),
circle(-9,-2,0.1),red(line(-14,-1,7,-1)),
red(circle(-9,-2,1)),locate(-4.8,-1,red(x=-1))
)}}}
The square of the distance between circle center {{{C}}}
and any circle point {{{P(x[P],y[P])}}} is
{{{(x-x[C])^2+(y-y[C])^2=R^2}}} .
That is true for all points in any circle, with any center and any radius.
That is the equation of a circle.
For this circle,
{{{(x-(-9))^2+(y-(-2))^2=1^2}}} simplifies to
{{{highlight((x+9)^2+(y+2)^2=1)}}} .