Question 1074097
 The sum of 5 consecutive even integers is 300.
 Let x be the second integer .
(n-2) + n + (n+2) + (n+4) + (n+6) = 300
5n + 10  = 300
5n = 290
n = 290/5
n = 58 is the 2nd integer
:
 What are the five integers?
56, 58, 60, 62, 64