<PRE><B>Question 94557</B>
Sum of 2 numbers is 71. The second is 6 more than 4 times the first. What are the 2 numbers.


Let first number = x

The second number = 4x+6

THe sum of the two numbers = 71

x+(4x+6) = 71

x+4x+6 = 71

5x+6 = 71

5x+6-6 = 71-6

5x = 65

5x/5 = 65/5

x = 13

CHECK

x+4x+6 = 71

13+4(13) +6 =71

71 = 71 

LHS = RHS

Hence x = 13 is the solution


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