Question 94542
x^3-x^2-12x=0

Take x as common factor

x(x^2-x -12) = 0

x = 0

x^2 -x -12 = 0

Factorize the above trinomial equation by middle term factorization


x^2 -4x +3x -12 =0

x(x-4) +3(x-4) = 0    (taking common factor)

(x+3)(x-4) = 0         (factors of the trinomial equation)

x+3 = 0

x+3-3 = 0-3

x = -3

x-4 = 0 

x-4+4 = 0+4

x = 4


Hence x = 0 , -3,  4 is the solution for the above polynomial equation