Question 1073899
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Solve by using the quadratic formula:


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{{{ 4x^2+1}}} = {{{8x }}}

Here's my work:
a= 4                                           correct
b= -8                                          correct
c= 1                                           correct

 -(-8) +/- sqrt((-8)^2-4(4)(1)/8               You missed one parenthesis  -(-8) +/- sqrt((-8)^2-4(4)(1))/8

 8 +/- sqrt(48)/8                              correct

I don't know what to do after that             = {{{(8 +- sqrt(16*3))/8}}} = {{{(8 +- 4sqrt(3))/8}}} = {{{1 +- (1/2)*sqrt(3)}}}.  It is your final answer.

Thanks!!!                                      Please.
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