Question 1073846
{{{5=(x-2)(x+2)}}}


*RESULT:{{{system(x=-3,or,x=3)}}}






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steps
* {{{log(5,(x-2))+log(5,(x+2))=1}}}-----(this step indicates that -3 will not work.)
{{{log(5,(x^2-4))=1}}}
{{{5^1=x^2-4}}}
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