Question 1073812
<pre><b>
{{{x^2+13x+12}}}

See the 12 on the right end?
See the + sign before the 12?  
See the 13 in the middle?

Think of two positive integers that when multiplied give 12,
but when ADDED (because the sign of 12 is +) gives 13.

We think of 12 and 1 because 12×1=12 and 12+1=13

S we write this

(x 12)(x 1)

Now since the sign of 12 is +, the signs will both be
the same.  What sign? We look at the sign in the middle,
the sign of 13.  It is +, so we put +'s in both parentheses:

(x+12)(x+1)

That's it.

We check by FOIL and get

x²+x+12x+12

which simplifies to:

x²+13x+12

So it checks.

Answer: (x+12)(x+1)

Edwin</pre>