Question 1073783
Let n be the speed of the slower car. Then the faster car is going n+3. So:
816/n=816/(n+3) + 1
816(n+3)=816n+n²+3n
n²+3n-2448=0
(n+51)(n-48)=0
n=48 or -51
The first car travels at 48 mph; the second car travels at 51 mph. &#9786;&#9786;&#9786;&#9786;