Question 1073738
Do you mean  {{{sqrt(112)-sqrt(63)+224/sqrt(28)}}}?
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Use sqrt(112) if you mean the square root of 112.
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{{{sqrt(112)-sqrt(63)+224/sqrt(28)=sqrt(16*7)-sqrt(9*7)+224/(sqrt(4*7))}}}
{{{sqrt(112)-sqrt(63)+224/sqrt(28)=4*sqrt(7)-3*sqrt(7)+224/(2*sqrt(7))}}}
{{{sqrt(112)-sqrt(63)+224/sqrt(28)=sqrt(7)+112/sqrt(7)}}}
{{{sqrt(112)-sqrt(63)+224/sqrt(28)=sqrt(7)+(112/sqrt(7))(sqrt(7)/sqrt(7))}}}
{{{sqrt(112)-sqrt(63)+224/sqrt(28)=sqrt(7)+(112/7)sqrt(7)}}}
{{{sqrt(112)-sqrt(63)+224/sqrt(28)=sqrt(7)+16*sqrt(7)}}}
{{{sqrt(112)-sqrt(63)+224/sqrt(28)=highlight(17*sqrt(7))}}}