Question 1073569
Complete the square,
{{{x^2-3x+39=0}}}
{{{(x^2-3x+(3/2)^2)+39=(3/2)^2}}}
{{{(x-3/2)^2+39=9/4}}}
{{{(x-3/2)^2=9/4-39}}}
{{{(x-3/2)^2=9/4-156/4}}}
{{{(x-3/2)^2=-147/4}}}
{{{x-3/2=0 +- (sqrt(147)/2)i}}}
{{{x=3/2 +- (sqrt(147)/2)i}}}
{{{x=(3 +- sqrt(147)i)/2)i}}}