Question 1073573
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I need help solving a trigonometry equation with a given interval.
solve the equation on the interval 0 is less than or equal to theta which is less than 2pin

4 sin theta+3=5
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1.  Your writing is INCORRECT. Your interval is 0 <= {{{theta}}} < {{{2pi}}}  (not 2pin).


2.  {{{4*sin(theta) + 3}}} = 5 ---->

    {{{4*sin(theta)}}} = 5 -3 ----> {{{4*sin(theta)}}} = 2 ---->  {{{sin(theta)}}} = {{{2/4}}}  ---->  {{{sin(theta)}}} = {{{1/2}}}.


    In the given interval, the solutions are  x = {{{pi/6}}}  and  x = {{{5pi/6}}}.
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