Question 1073416
Let n be the amount of 60% alcohol. Then the amount of 30% alcohol would be 90-n. So:
.6n+.3(90-n)=.5(90)
.3n+27=45
.3n=18
n=60
60 liters of .6 alcohol and 30 liters of .3 alcohol will give you the desired mixture. &#9786;&#9786;&#9786;&#9786;