Question 1060437
25^(10x+8)=(1/125)^(4-2x)
(5^2)^(10x+8)=(5^-3)^4-2x
5^(20x+16)=5^(-12+6x)
20x+16=6x-12
14x=-28
x=-2. &#9786;&#9786;&#9786;&#9786;