Question 1060615
1/125^(aČ+4ab)=(625^(1/3))^(3aČ-10ab)
(5^-3)^(aČ+4ab)=((5^4)^(1/3))^(3aČ-10ab)
5^(-3aČ-12ab)=5^4aČ-40ab/3
-3aČ-12ab=4aČ-(40ab/3)
-9aČ-36ab=12aČ-40ab
4ab=21aČ
4b=21a
21a/b=4
a/b=4/21. ☺☺☺☺