Question 1073370
average is n * p = 10 * .1 = 1
standard error is sqrt(n * p * q) = sqrt(10 * .1 * .9) = .94868...


this is normal distribution of a proportion.


here's a reference.


<a href = "http://www.math.ubc.ca/~feldman/m302/binomial.pdf" target = 
"_blank">http://www.math.ubc.ca/~feldman/m302/binomial.pdf</a>


lots of math in there, but the punch line is what's enclosed in the boxes.


mean = n * p.


variance = n * p * q


q = 1 - p


standard deviation is sqrt (n * p * q)